NEET 2013 Question Paper with Solution
NEET (National Eligibility cum Entrance Test) 2013 was conducted by the Central Board of Secondary Education (CBSE) for students seeking admission to MBBS and BDS courses in medical colleges across India. This comprehensive analysis covers the question paper structure, important questions with detailed solutions, and insights into the examination pattern.
The NEET 2013 was conducted on 5th May 2013. The exam comprised three sections:
The paper had 180 questions in total, with 45 questions in each subject. Each correct answer carried 4 marks, while each incorrect response led to a deduction of 1 mark (negative marking).
The Physics section of NEET 2013 had a good balance of theoretical and numerical-based questions. Class XI and Class XII syllabuses were evenly distributed.
Q1. A particle moves with simple harmonic motion in a straight line. In the first seconds, after starting from rest it travels a distance a, and in next seconds it travels 2a in same direction, then:
A. amplitude = 3a
B. time period = 8
C. amplitude = 4a
D. time period = 6
Solution:
For a particle in SHM starting from rest (at extreme position), the displacement after time t is given by x = A cos(t).
At t = , displacement = a = A - A cos()
At t = 2, displacement = 3a = A - A cos(2)
Using cos(2) = 2cos() - 1, we get:
3a = A - A(2cos() - 1)
3a = 2A - 2Acos()
From the first equation: cos() = 1 - a/A
Substituting this into the second equation:
3a = 2A - 2A(1 - a/A)
Solving, we get A = 4a (amplitude)
cos() = 1 - a/4a = 3/4
Therefore, = cos(3/4)
The time period T = 2/ = 2/cos(3/4)
For this particular problem, T = 8
Answer: B
Q2. Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, then the number of electrons missing from each ion will be:
A. q/F
B. (4Fd/q)/
C. (qF/4d)/
D. (q/4Fd)/
Solution:
By Coulomb's law: F = (1/4) (q/d)
Solving for q: q = (4Fd)/
Since q = ne, where n is the number of extra electrons (or missing electrons for positive ions):
n = q/e = (4Fd/e)/
This can be rewritten as n = (4Fd/q)/
Answer: B
The Chemistry section of NEET 2013 covered Organic, Inorganic, and Physical Chemistry with approximately equal weightage.
Q3. The correct order of N-compounds in its decreasing order of oxidation states is:
A. HNO, NO, N, NHCl
B. HNO, NO, NHCl, N
C. HNO, NHCl, NO, N
D. NHCl, N, NO, HNO
Solution:
Let's determine the oxidation state of nitrogen in each compound:
Arranging in decreasing order of oxidation states:
HNO (+5) > NO (+2) > N (0) > NHCl (-3)
Answer: A
Q4. Which of the following complexes is optically inactive?
A. [Co(en)]
B. [Co(en)Cl] (cis)
C. [Co(en)Cl] (trans)
D. [Cr(ox)]
Solution:
A complex is optically active if it lacks a plane of symmetry and a center of symmetry, meaning it has non-superimposable mirror images (chirality).
Answer: C
The Biology section had 45 questions each from Botany and Zoology, covering various topics from NCERT textbooks.
Q5. Which one of the following is wrong statement?
A. Phylum-Annelida has an organ system level of organization
B. Phylum-Arthropoda has segmented body
C. Phylum-Mollusca has a closed circulatory system
D. Phylum-Chordata has notochord
Solution:
Let's analyze each statement:
Answer: C
Q6. Which one of the following is common to multicellular fungi, filamentous algae and protonema of mosses?
A. Diplontic life cycle
B. Members of kingdom Plantae
C. Mode of nutrition
D. Multicellularity
Solution:
Let's analyze each option:
Answer: D
| Subject | Easy Questions | Medium Questions | Difficult Questions |
|---|---|---|---|
| Physics | 15 | 20 | 10 |
| Chemistry | 18 | 17 | 10 |
| Biology | 20 | 18 | 7 |
Physics:
Chemistry:
Biology:
NEET 2013 was a balanced paper testing students across all subjects. The moderate difficulty level allowed well-prepared students to score well. Understanding the pattern and types of questions asked can help future aspirants prepare more effectively for the examination. Regular practice of previous year papers like NEET 2013 is essential for building confidence and improving time management skills.
