Triple integrals extend the concept of integration to functions of three variables over three-dimensional regions. Just as single integrals accumulate values along a line and double integrals accumulate values over a two-dimensional area, triple integrals accumulate values throughout volumes.
The concept of triple integration is fundamental to many areas of mathematics and physics, including fluid dynamics, electromagnetism, probability theory, and engineering calculations involving mass, momentum, and energy distribution through three-dimensional bodies.
Geometrically, if f(x,y,z) = 1, the triple integral over a region E represents the volume of that region. More generally, the triple integral E f(x,y,z) dV can be interpreted as accumulating the weighted "content" throughout the region, where each infinitesimal volume element dV is weighted by the function value f(x,y,z).
A triple integral is typically written as:
Where:
In Cartesian coordinates, the triple integral becomes:
The limits of integration define the region E. The outer integral's limits are constants, while the inner integrals' limits may be functions of the outer variables.
Triple integrals are evaluated by performing successive integrations, starting from the innermost integral and working outward. Each integration treats all variables except the one being integrated as constants.
Evaluate 01 02 03 (x+y+z) dz dy dx
First, integrate with respect to z: (x+y+z) dz = [xz + yz + z/2] = 3x + 3y + 9/2
Next, integrate with respect to y: (3x + 3y + 9/2) dy = [3xy + 3y/2 + (9/2)y] = 6x + 6 + 9 = 6x + 15
Finally, integrate with respect to x: (6x + 15) dx = [3x + 15x] = 3 + 15 = 18
In Cartesian coordinates, the volume element is simply dV = dx dy dz, and the integral takes the form shown above. This is the most straightforward coordinate system when working with rectangular regions.
Cylindrical coordinates (r,,z) are useful when dealing with problems involving cylindrical symmetry. The relationship to Cartesian coordinates is:
With the volume element dV = r dr d dz, the triple integral becomes:
Spherical coordinates (,,) are ideal for problems with spherical symmetry, such as when integrating over spheres or portions of spheres. The relationship to Cartesian coordinates is:
With the volume element dV = sin() d d d, the triple integral becomes:
The simplest application of triple integrals is finding the volume of a three-dimensional region. If f(x,y,z) = 1, then E dV gives the volume of region E.
Find the volume of a sphere with radius R using spherical coordinates.
The region is 0 R, 0 , 0 2.
Volume = R sin() d d d
= [/3]R sin() d d
= (R/3) sin() d d
= (R/3) [-cos()] d
= (R/3) 2 d
= (2R/3) d
= (2R/3) 2
= (4/3)R
Which matches the well-known formula for the volume of a sphere!
If a three-dimensional object has a variable density function (x,y,z), then its mass can be found by integrating the density over the volume:
The coordinates of the center of mass (x, , ) of a three-dimensional object with density function (x,y,z) are:
Moments of inertia, important in rotational mechanics, can also be calculated using triple integrals:
Evaluate E (x + y + z) dV where E is the rectangular box [0,1] [0,2] [0,3].
Solution:
(x + y + z) dx dy dz
First, integrate with respect to x: (x + y + z) dx = [x/3 + x(y + z)] = 1/3 + y + z
Next, integrate with respect to y: (1/3 + y + z) dy = [y/3 + y/3 + yz] = 2/3 + 8/3 + 2z = 10/3 + 2z
Finally, integrate with respect to z: (10/3 + 2z) dz = [10z/3 + 2z/3] = 10 + 18 = 28
Therefore, (x + y + z) dx dy dz = 28
Evaluate E z dV where E is the region bounded by the cylinder x + y = 4 and the planes z = 0 and z = 5.
Solution: Using cylindrical coordinates:
The region is 0 r 2, 0 2, 0 z 5
zr dr d dz
First, integrate with respect to r: zr dr = z[r/2] = 2z
Next, integrate with respect to : 2z d = 2z[] = 4z
Finally, integrate with respect to z: 4z dz = 4[z/2] = 4(25/2) = 50
Therefore, E z dV = 50
Evaluate E (x + y + z) dV where E is the region enclosed by the sphere x + y + z = 9.
Solution: Using spherical coordinates:
The region is 0 3, 0 , 0 2
Since x + y + z = in spherical coordinates, we have f(,,) =
sin() d d d
First, integrate with respect to : d = [/5] = 243/5
Next, integrate with respect to : (243/5) sin() d = (243/5)[-cos()] = (243/5)(2)
Finally, integrate with respect to : (486/5) d = (486/5)[] = (486/5)(2)
Therefore, E (x + y + z) dV = (972/5)
Explore different types of 3D regions and their integrals:
Select a region type:
Triple integrals satisfy linearity properties similar to single integrals:
If E can be decomposed into non-overlapping regions E, E, ..., E, then:
Fubini's Theorem extends to triple integrals, stating that if f is continuous on a rectangular region R = [a,b] [c,d] [e,f], then:
When changing variables from (x,y,z) to (u,v,w) via transformation x = x(u,v,w), y = y(u,v,w), z = z(u,v,w), the integral becomes:
Where |J| is the absolute value of the Jacobian determinant.
The Divergence Theorem (Gauss's Theorem) connects triple integrals to surface integrals:
Where F is a vector field, F is its divergence, E is the boundary surface of region E, and n is the outward unit normal to E.
Triple integrals are powerful mathematical tools that allow us to:
