Fall 2019Math 201: Calculus and Analytic Geometry III
Lecture 8: Sections 26-28
This lecture covers key concepts from Calculus III including vector fields, line integrals, and surface integrals. We'll explore these topics with a focus on practical applications and problem-solving techniques.
A vector field is a function that assigns a vector to each point in space. In two dimensions, we can represent a vector field as F(x, y) = M(x, y)i + N(x, y)j, where M and N are functions of x and y.
A vector field F is conservative if:
Determine whether the vector field F(x, y) = (2xy + y)i + (x + 2xy)j is conservative.
Solution: We can check if M/y = N/x.
M/y = /y(2xy + y) = 2x + 2y
N/x = /x(x + 2xy) = 2x + 2y
Since M/y = N/x, the vector field is conservative.
Vector fields have numerous applications in physics, including:
A line integral is an integral where the function to be integrated is evaluated along a curve. There are several types of line integrals:
For a curve parameterized by r(t) = (x(t), y(t), z(t)) for a t b, the line integral becomes:
C F dr = [a to b] F(r(t)) r'(t) dt
For a conservative vector field F = f, we have:
C f dr = f(r(b)) - f(r(a))
Calculate C yx dx + xy dy along the path from (0, 0) to (1, 1) given by y = x.
Solution: Parameterize the curve as x = t, y = t for 0 t 1.
Then dx = dt and dy = 2t dt.
Substituting into the integral:
[0 to 1] (t)tdt + t(t)2tdt
= [0 to 1] (t + 2t) dt
= [t/6 + 2t/7] from 0 to 1
= 1/6 + 2/7 - 0 = 19/42
Line integrals are used to calculate:
Electromagnetic work
Surface integrals extend line integrals to two-dimensional surfaces in three-dimensional space. A surface integral of a scalar function f over a surface S is given by:
S f(x, y, z) dS = D f(r(u, v)) |r_u r_v| dA
where D is the parameter domain and r(u, v) is a parameterization of the surface.
The flux of a vector field F across a surface S with unit normal vector n is:
Flux = S F n dS
Calculate the flux of F = xi + yj + zk through the upper hemisphere x + y + z = 4, z 0.
Solution: Use spherical coordinates to parameterize the surface:
x = 2sin()cos(), y = 2sin()sin(), z = 2cos()
For 0 2, 0 /2.
The outward unit normal is n = (x/2)i + (y/2)j + (z/2)k = sin()cos()i + sin()sin()j + cos()k.
F n = xsin()cos() + ysin()sin() + zcos()
= 4sin()cos()sin()cos() + 4sin()sin()sin()sin() + 4cos()cos()
= 4sin()cos() + 4sin()sin() + 4cos()
= 4sin() + 4cos() = 4
Flux = S F n dS = [0 to 2][0 to /2] 42sin() d d
= 16[0 to 2][0 to /2] sin() d d
= 16[0 to 2] [-cos()][0 to /2] d
= 16[0 to 2] [0 - (-1)] d
= 16[0 to 2] 1 d = 32
Surface integrals are used to calculate:
D F dr = D (N/x - M/y) dA
where F = Mi + Nj is a vector field on an open region containing D, and D is the positively oriented boundary curve of D.
S F dr = S ( F) n dS
relating the line integral of a vector field around a boundary curve S to the surface integral of the curl of the vector field over the surface S.
E F n dS = E ( F) dV
relating the flux of a vector field through a closed surface E to the divergence of the field within the enclosed volume E.
Determine whether the vector field F(x, y) = (y - 2x)i + (2xy + 3)j is conservative. If it is, find a potential function.
Calculate C 2xy dx + xy dy, where C is the triangle with vertices (0, 0), (1, 0), and (1, 2).
Find the flux of F = xi - j + zk through the surface S: x + 2y + 3z = 6 in the first octant, in the direction away from the origin.
In Lecture 8, we explored vector fields, line integrals, and surface integrals - fundamental concepts in multivariable calculus. We learned how to determine if a vector field is conservative and how to calculate various types of integrals over curves and surfaces. These tools provide powerful methods for solving physical problems involving work, circulation, flux, and other important quantities. The theorems of Green, Stokes, and the Divergence Theorem connect seemingly different types of integrals and are essential for advanced applications in mathematics, physics, and engineering.
