In multivariable calculus, the concepts of limits and continuity extend naturally from single-variable calculus to functions of multiple variables. These concepts are fundamental in fields such as physics, engineering, and applied mathematics.
A function of two variables, f(x, y), assigns a numerical value to each point (x, y) in some region of the plane. Similarly, a function of three variables, f(x, y, z), assigns a numerical value to each point (x, y, z) in three-dimensional space.
Let f be defined on a deleted neighborhood of (a, b). We say that the limit of f(x, y) as (x, y) approaches (a, b) is L, denoted as lim(x,y)(a,b) f(x, y) = L, if for every > 0, there exists a > 0 such that |f(x, y) - L| < whenever 0 < [(x-a) + (y-b)] < .
This definition is analogous to the definition of a limit for a function of a single variable, but instead of approaching a point on a number line, we approach a point in the plane. For functions of three variables, the definition is similar with (x, y, z) approaching (a, b, c).
The limit properties for single-variable functions extend to multivariable functions:
Find lim(x,y)(1,2) (x + 3y).
Solution: This is a polynomial function, which is continuous everywhere. Therefore, we can directly substitute:
lim(x,y)(1,2) (x + 3y) = 1 + 3(2) = 1 + 6 = 7
Find lim(x,y)(0,0) (x - y)/(x + y).
Solution: Approaching along y = 0: limit = 1. Approaching along x = 0: limit = -1.
Since the limits along different paths are different, the limit does not exist.
Find lim(x,y)(0,0) (xy)/(x + y).
Solution: In polar coordinates where x = rcos() and y = rsin(), the expression becomes: cos()sin()
This depends on , so the limit does not exist (it varies depending on the direction of approach).
A function f(x, y) is continuous at a point (a, b) if:
Many of the properties of continuous functions in single-variable calculus extend to multivariable functions:
Extreme Value Theorem: If f is continuous on a closed and bounded region, then f attains both a maximum value and a minimum value on that region.
Intermediate Value Theorem: If f is continuous on a connected set and k is any value between f(a) and f(b) for some points, then there exists a point where f equals k.
Determine whether the function f(x, y) = xy/(x + y) for (x, y) (0, 0) and f(0, 0) = 0 is continuous at (0, 0).
Solution: Approaching along y = kx gives limit = k/(1 + k), which depends on k.
Since the limit does not exist, the function is not continuous at (0, 0).
The temperature T at a point (x, y, z) is given by T(x, y, z) = x + y - 2z + 10. Find the temperature and its limit as the point approaches (2, 1, 0).
Solution: Since T is a polynomial function, it is continuous everywhere. Therefore:
lim(x,y,z)(2,1,0) T(x, y, z) = T(2, 1, 0) = 2 + 1 - 20 + 10 = 15
The temperature at (2, 1, 0) is 15 units.
Limits and continuity of functions of two or three variables extend the fundamental concepts of single-variable calculus to multivariable settings. The definitions are analogous but involve approaching a point in the plane or in space rather than on a number line.
These concepts are crucial for understanding more advanced topics in multivariable calculus, such as partial derivatives, gradients, and multiple integrals. They also have numerous applications in physics, engineering, and other sciences where phenomena are modeled by functions of multiple variables.
The main challenge when working with limits of multivariable functions is that there are infinitely many paths of approach to a point. This is why showing that a limit exists often requires more sophisticated techniques than those used in single-variable calculus.
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