Class XII Physics sample question papers serve as essential tools for students preparing for their board examinations. These papers, designed according to the latest curriculum and examination patterns, provide insights into question formats, marking schemes, and topic distribution. By working through them, students can familiarize themselves with the examination structure and practice various types of questions.
The Class XII Physics question paper is typically divided into several sections:
| Section | Type of Questions | Marks per Question | Total Marks |
|---|---|---|---|
| A | Very Short Answer Questions | 1 | 5 |
| B | Short Answer Questions I | 2 | 10 |
| C | Short Answer Questions II | 3 | 21 |
| D | Value Based Questions | 4 | 4 |
| E | Long Answer Questions | 5 | 20 |
Class XII Physics encompasses a wide range of concepts across different units:
Question 1: Define electric dipole moment. Write its SI unit.
Answer: Electric dipole moment is defined as the product of magnitude of either charge and the distance between the two charges. Its SI unit is coulomb-meter (Cm).
Question 2: What is meant by the term 'drift velocity' of electrons?
Answer: Drift velocity is the average velocity with which free electrons get drifted in a conductor under the influence of an electric field.
Question 1: State and prove Gauss's law in electrostatics.
Answer: Gauss's law states that the total electric flux through any closed surface (called Gaussian surface) is equal to (1/) times the total charge enclosed by the surface.
Proof: Consider a point charge q at the center. Draw a sphere of radius r around it. The electric field at all points on the sphere is E = (1/4)(q/r). The flux through the sphere is = E 4r = (1/4)(q/r) 4r = q/.
Question 2: Derive the expression for the force between two parallel current-carrying conductors.
Answer: Consider two parallel conductors carrying currents I and I, separated by distance r. The magnetic field produced by I at the location of I is B = (/4)(2I/r). The force per unit length on conductor 2 is F = I B = I (/4)(2I/r) = (/2)(II/r). This gives the attractive force between conductors carrying currents in the same direction.
Question 1: Derive the mirror formula for a concave mirror.
Answer: Consider a concave mirror with focus F and center of curvature C. Let an object be placed at point O. Using ray diagrams and geometry, we can derive the mirror formula: 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance. This formula relates object distance, image distance, and focal length for spherical mirrors.
Question 2: Explain the principle of a potentiometer. Describe how it can be used to compare the emf of two primary cells.
Answer: A potentiometer works on the principle that the potential drop across a uniform wire is directly proportional to its length when a constant current flows through it. To compare the emf of two cells, we first connect one cell (E) to the potentiometer and find the balancing length l. Then replace it with the second cell (E) and find the new balancing length l. Since the potential drop per unit length remains constant, we have E/E = l/l, allowing us to compare the emf of the two cells.
Question 1: Rajan's family was facing voltage fluctuations in their area. His father, an electrical engineer, installed a voltage stabilizer at their home. When Rajan asked the reason for installing the stabilizer, his father explained the working principles. Based on this scenario:
a) What is voltage fluctuation? Why is it harmful?
b) How does a voltage stabilizer work?
c) What values are displayed by Rajan's father?
Answer: a) Voltage fluctuation refers to the continuous change in voltage level above or below the normal range. It can damage electronic appliances and reduce their lifespan.
b) A voltage stabilizer maintains the output voltage at a desired level despite changes in input voltage. It consists of an autotransformer with multiple taps and electronic circuits that detect voltage changes and automatically select the appropriate tap.
c) Rajan's father shows values of responsibility towards family welfare, knowledge-sharing, and practical application of technical skills to solve real-life problems.
Question 1: a) Derive the expression for the energy stored in a parallel plate capacitor.
b) A parallel plate capacitor with air between the plates has a capacitance of 8 pF. What will be the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 6?
Answer: a) When charging a capacitor, work is done to move charge from one plate to another against the electric field. The potential difference across the capacitor is V = Q/C. The work done in moving a small charge dq against potential difference V is dW = Vdq = (q/C)dq. Integrating from 0 to Q, we get W = ^Q (q/C)dq = Q/(2C). This work done is stored as potential energy: U = Q/(2C) = CV = QV.
b) For a parallel plate capacitor, C = A/d. When the distance is halved (d' = d/2) and the space is filled with a dielectric (k = 6), the new capacitance C' = kA/d' = 6A/(d/2) = 12A/d = 12C. Substituting C = 8 pF, we get C' = 12 8 pF = 96 pF.
Recent examination trends indicate increased emphasis on conceptual understanding and application-based questions. Questions involving real-life applications of physics principles have become more common. The paper often includes:
For effective preparation:
Class XII Physics sample question papers are invaluable resources for comprehensive exam preparation. By systematically working through these papers, students can enhance their understanding of core concepts, improve problem-solving skills, and develop confidence for the actual examination. Regular practice with diverse question types strengthens both theoretical knowledge and practical application abilities, essential for success in physics examinations.
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