Calculus II - Section 7.7 #24: Approximate Integration
Introduction
Approximate integration techniques are essential tools when we encounter definite integrals that cannot be evaluated exactly using the Fundamental Theorem of Calculus. Section 7.7 introduces several methods for numerical integration, including the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule.
Problem #24
Problem Statement
Use the following methods to approximate the integral e dx with an error less than or equal to 0.001:
- Trapezoidal Rule
- Midpoint Rule
- Simpson's Rule
Solution Approach
Let's examine the integral we're approximating:
I = e dx
This integral cannot be expressed in terms of elementary functions, making numerical approximation necessary. To achieve the required precision ( 0.001), we must determine the appropriate number of subintervals (n) for each method using their respective error estimation formulas:
Applying the Trapezoidal Rule
Finding the Required Number of Subintervals
For f(x) = e, we first find f''(x):
f'(x) = 2xe
f''(x) = e(4x + 2)
On [0,2], the maximum value of |f''(x)| occurs at x=2:
K = f''(2) = 18e 982.656
Using the error bound formula for the Trapezoidal Rule:
|E| K(b-a)/12n
Solving for n with |E| 0.001:
982.656(2-0)/12n 0.001
n 982.6568/120.001 655,104
n 655,104 809.4
Thus, we need at least n = 810 subintervals for the Trapezoidal Rule.
Implementing the Trapezoidal Rule
The Trapezoidal Rule formula is:
f(x)dx (b-a)/2n [f(x) + 2f(x) + 2f(x) + ... + 2f(x) + f(x)]
With n = 810 and x = (2-0)/810, applying the formula yields approximately:
e dx 16.452
Applying the Midpoint Rule
The error bound for the Midpoint Rule requires fewer subintervals:
|E| K(b-a)/24n
Solving for n:
982.656(2-0)/24n 0.001
n 327,552 572.3
Thus, we need at least n = 573 subintervals for the Midpoint Rule.
The Midpoint Rule formula is:
f(x)dx (b-a)/n [f(m) + f(m) + ... + f(m)]
where mi is the midpoint of the ith subinterval.
With n = 573, applying the formula yields approximately:
e dx 16.453
Applying Simpson's Rule
Finding the Fourth Derivative
For Simpson's Rule, we need f(x):
f(x) = e(16x + 48x + 12)
On [0,2], the maximum value of |f(x)| occurs at x=2:
K = f(2) = 460e 25,101.4
Determining the Required Subintervals
Using the error bound formula for Simpson's Rule:
|E| K(b-a)/180n
Solving for n:
25,101.4(2-0)/180n 0.001
n 7,136.4 9.2
Since Simpson's Rule requires an even number of subintervals, we need n = 10.
Implementing Simpson's Rule
Simpson's Rule formula is:
f(x)dx (b-a)/3n [f(x) + 4f(x) + 2f(x) + 4f(x) + ... + 4f(x) + f(x)]
Notice the pattern of coefficients: 1,4,2,4,2,...,4,1
With n = 10, we calculate the following values:
| i | xi | f(xi) | Weight | Weighted Value |
| 0 | 0 | 1 | 1 | 1 |
| 1 | 0.2 | 1.0408 | 4 | 4.1632 |
| 2 | 0.4 | 1.1735 | 2 | 2.3470 |
| 3 | 0.6 | 1.4333 | 4 | 5.7332 |
| 4 | 0.8 | 1.8965 | 2 | 3.7930 |
| 5 | 1.0 | 2.7183 | 4 | 10.8732 |
| 6 | 1.2 | 4.2207 | 2 | 8.4414 |
| 7 | 1.4 | 7.0993 | 4 | 28.3972 |
| 8 | 1.6 | 12.9358 | 2 | 25.8716 |
| 9 | 1.8 | 25.5335 | 4 | 102.1340 |
| 10 | 2.0 | 54.5982 | 1 | 54.5982 |
Sum of weighted values: 246.3518
Applying Simpson's Rule:
e dx (2-0)/310 246.3518 16.453
Comparison and Analysis
The results from our three methods are:
- Trapezoidal Rule (n=810): 16.452
- Midpoint Rule (n=573): 16.453
- Simpson's Rule (n=10): 16.453
Key Observation: Simpson's Rule achieved the requested precision with only 10 subintervals, while the Trapezoidal Rule required 810 and the Midpoint Rule required 573. This demonstrates the superior efficiency of Simpson's Rule for smooth functions like e.
Conclusion
Problem #24 illustrates the practical application of approximate integration techniques. Each method has advantages:
- Simpson's Rule: Most efficient for smooth functions
- Midpoint Rule: Generally requires about half the subintervals of the Trapezoidal Rule for the same accuracy
- Trapezoidal Rule: Simple to implement but often requires many more subintervals
Common Mistakes to Avoid
- Forgetting to check the maximum value of derivatives over the entire interval when calculating error bounds
- Not using an even number of subintervals for Simpson's Rule
- Calculation errors when implementing the formulas, especially with alternating coefficients in Simpson's Rule
- Not recognizing when a function's behavior requires special consideration (e.g., sharp changes in slope)
Related Topics
- Numerical differentiation
- Improper integrals and their numerical approximation
- Error analysis in numerical methods
- Adaptive quadrature methods
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